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  1. 3 cze 2021 · To have the exact evaluation distance you need you can consider to create the planes of your cube with the plane class. Then you can obtain the distance with Plane.ClosestPointOnPlane, that is the smalles distance in plane's normal direction, the distance that you need.

  2. 21 paź 2009 · The distance between the two vectors is this vector's length (or 'magnitude', a property which Unity handily provides for you), which you could manually calculate by using some trigonometry: Code (csharp): float distance = Math.Sqrt(. Math.Pow( difference.x, 2f) +.

  3. 17 mar 2010 · A more mathematical approach, you could use the Pythagorean Theorem and calculate the hypotenuse using the right triangle with the grid units in unity. So, the square root of (delta)X^2 + (delta)Z^2 = flatdistance (this is a var) and then… square root of flatdistance^2 + (delta)Y^2 = distance between the two points

  4. Description. Returns the distance between a and b. Vector3.Distance(a,b) is the same as (a-b).magnitude. using UnityEngine; using System.Collections; public class ExampleClass : MonoBehaviour . { public Transform other; void Example() { if (other) { float dist = Vector3.Distance (other.position, transform.position);

  5. 1 sty 2010 · Vector3.Distance can be used if you want to determine the distance between two gameobjects. Vector2.Distance can be used if you're making a 2D game, or for GUI elements(for example, determining how far the mouse traveled over a series of frames.)

  6. 12 sty 2017 · Here is an example of a method that will determine the orthographic distance between two Vector3 coordinates, and output the value as a float. public float GetOrthographicDistance(Vector3 a, Vector3 b) { return Vector2.Distance( new Vector2(a.x, a.y), new Vector2(b.x, b.y)); }

  7. 2 gru 2019 · GameObject nearest; void Start() { var distance = Mathf.Infinity; var position = transform.position; var objects = GameObject.FindGameObjectsWithTag("Tag"); foreach(GameObject thisObject in objects) { var diff = (thisObject.transform.position - position); var curDistance = diff.sqrMagnitude; if(curDistance < distance) { nearest = thisObject ...

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