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Displacement diagrams are effectively plotting the displacement vectors of the joints as defined by the end of the bars. The displacement vector for the end of a bar is made up of two components: (1) an extension, of a magnitude defined by the bar force and the constitutive behavior of the bar which is parallel to the direction of the bar and (2) a
We determine the constants of integration by evaluating our expression for displacement v(x) and/or our expression for the slope dv/dx at points where we are sure of their val-ues. One such boundary condition is that, at x=0 the displacement is zero, i.e., vx()= 0 x = 0 Another is that, at the support point B, the displacement must vanish, i.e.,
Displacement diagram (to Scale) Horizontal Displacement = PL AE to the left vertical displacement = 12.9 PL AE
In the linear portion of the stress-strain diagram, the tress is proportional to strain and is given by $\sigma = E \varepsilon$ since $\sigma = P / A$ and $\varepsilon = \delta / L$, then $\dfrac{P}{A} = E \dfrac{\delta}{L}$ $\delta = \dfrac{PL}{AE} = \dfrac{\sigma L}{E}$ To use this formula, the load must be axial, the bar must have a uniform ...
Consider the beam of Fig. 1.14 axially loaded along the x axis in com-pression. If a small load or displacement is applied laterally at the location of the axial load, the beam bends slightly. If the lateral load is removed, the beam returns to its straight position.
The expression for deformation and a given load \(\delta = PL/AE\) applies just as in tension, with negative values for \(\delta\) and \(P\) indicating compression.
Let's learn how to calculate displacements from v-t graphs. We will see why the area under the v-t graph gives displacement. Created by Mahesh Shenoy.
