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  1. 6 godz. temu · x = (v0cosθ)t y = − 1 2gt2 + (v0sinθ)t + h. where g accounts for the effects of gravity and h is the initial height of the object. Depending on the units involved in the problem, use g = 32 ft/s2 or g = 9.8 m/s2. The equation for x gives horizontal distance, and the equation for y gives the vertical distance.

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